My Math Section

 The following symbols are used in articles of the math section. Just make sure you understand what they mean.

"^" means "the power of", 2^2 means 2 to the second power which equals 4.

"Sqrt" means "the square root of", Sqrt(9) means the square root of 9 which is 3

"(+,-)" means "plus or mines",4 (+,-) 6 means 4 plus or mines 6

"/" means divide

"*" means multiply

"=)"  a sign I invented, it means "next'

How does the Quadratic formula works

     Well, I know that the formula of the equation: "ax^2 + bx + c = 0"     is    "[-b (+,-) Sqrt(b^2 - 4ac)] / 2a"

   But most people ask "How does it work?", I am writing it down here so you can show off in front of other people that doesn't know anything about it. ^_^

    Formula to Equation:

 [-b (+,-) Sqrt(b^2 - 4ac)] / 2a = x

=) 2ax+b = (+,-) Sqrt(b^2 - 4ac)                          move the 2a and the -b to the other side

=) [2ax + b]^2 = [ (+,-) Sqrt(b^2 - 4ac)]^2          raise both sides to the second power so the Sqrt sign and the plus or mines sign canceled

=) [2ax + b] * [2ax + b] = b^2 - 4ac                     simplify both side

=) [2ax + b] * [2ax + b] - (b^2 - 4ac) = 0              move the right side to the left

=) [4 * a^2 * x^2 + 4axb + b^2] - b^2 + 4ac = 0  using the expanding method and the distributive property

=) 4 * a^2 * x^2 + 4axb + 4ac = 0                        cancel the positive b^2 and the negative b^2

=) 4 (a^2*x^2 + axb + ac) = 0                              pull out the common factor 4

=) a^2*x^2 + axb + ac = 0                                   divide both side by 4

=) a (a*x^2 + xb + c) = 0                                     pull out the common factor a 

=) ax^2 + xb + c = 0                                            divide each side by a

=) ax^2 + bx +c = 0                                             If that wasn't obvius enough, I put the b in front of the x

How does the Quadratic Formula works (second part)

 Now, equation to formula is a bit more complicated, you just need to understand that our main goal is to actually FACTOR the equation using the function : "a^2 + 2ab + b^2  =  (a+b)^2".
 

 ax^2 + bx +c = 0    

=) a(ax^2 + bx +c) = 0                                         Multiply both sides by an "a"

=) (ax)^2 + abx + ac = 0                                      Simplify

=) 2 [ (ax)^2 + abx + ac ] = 0                               Multiply both sides by 2

=) 2*(ax)^2 + 2axb + 2ac = 0                               Simplify

=) 2 [2*(ax)^2 + 2axb + 2ac] = 0                          Multiply both sides by 2 again

=) 4*(ax)^2 + 2*(2axb) + 4ac = 0                         Using the distributive property

=) (2ax)^2 + 2(2ax)b + 4ac  = 0                            Simplify

Now, think that "2ax" is "a", "b" is "b", we need another "b^2" in order to have the equation "a^2 + 2ab + b^2"

=)  (2ax)^2 + 2(2ax)b + b^2 - b^2 + 4ac  = 0         I added the b^2 and mines it, so the equation won't change

=) (2ax + b)^2 -b^2 + 4ac = 0                                e have a completed model of factoring, so factor it!

=) (2a x+ b)^2 = b^2 - 4ac                                     move the -b^2 + 4ac to the other side, our goal now is to find x

=) (+,-)(2ax + b) = Sqrt(b^2 - 4ac)                         add the Square root sign on both sides

=) 2ax + b = (+,-) Sqrt(b^2 - 4ac)                           move the plus or mines sign to the pther side

=) 2ax = -b (+,-) Sqrt(b^2 - 4ac)                             move the b to the other side

=) x = [-b (+,-) Sqrt(b^2 - 4ac)] / 2a                        divide both sides by 2a and now we have completed this whole process, and that's how the quadratic formula formed and worked.